3[a-2]+2[a-1]=2

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Solution for 3[a-2]+2[a-1]=2 equation:


Simplifying
3[a + -2] + 2[a + -1] = 2

Reorder the terms:
3[-2 + a] + 2[a + -1] = 2
[-2 * 3 + a * 3] + 2[a + -1] = 2
[-6 + 3a] + 2[a + -1] = 2

Reorder the terms:
-6 + 3a + 2[-1 + a] = 2
-6 + 3a + [-1 * 2 + a * 2] = 2
-6 + 3a + [-2 + 2a] = 2

Reorder the terms:
-6 + -2 + 3a + 2a = 2

Combine like terms: -6 + -2 = -8
-8 + 3a + 2a = 2

Combine like terms: 3a + 2a = 5a
-8 + 5a = 2

Solving
-8 + 5a = 2

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 5a = 2 + 8

Combine like terms: -8 + 8 = 0
0 + 5a = 2 + 8
5a = 2 + 8

Combine like terms: 2 + 8 = 10
5a = 10

Divide each side by '5'.
a = 2

Simplifying
a = 2

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